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1/6=5/2+p
We move all terms to the left:
1/6-(5/2+p)=0
Domain of the equation: 2+p)!=0We add all the numbers together, and all the variables
We move all terms containing p to the left, all other terms to the right
p)!=-2
p!=-2/1
p!=-2
p∈R
-(+p+5/2)+1/6=0
We get rid of parentheses
-p-5/2+1/6=0
We calculate fractions
There is no solution for this equation
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