1/6=r-19/r

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Solution for 1/6=r-19/r equation:


D( r )

r = 0

r = 0

r = 0

r in (-oo:0) U (0:+oo)

1/6 = r-(19/r) // - r-(19/r)

19/r-r+1/6 = 0

19*r^-1-1*r^1+1/6*r^0 = 0

(1/6*r^1-1*r^2+19*r^0)/(r^1) = 0 // * r^2

r^1*(1/6*r^1-1*r^2+19*r^0) = 0

r^1

(1/6)*r-r^2+19 = 0

(1/6)*r-r^2+19 = 0

DELTA = (1/6)^2-(-1*4*19)

DELTA = 2737/36

DELTA > 0

r = ((2737/36)^(1/2)-(1/6))/(-1*2) or r = (-(1/6)-(2737/36)^(1/2))/(-1*2)

r = ((2737/36)^(1/2)-1/6)/(-2) or r = ((2737/36)^(1/2)+1/6)/2

r in { ((2737/36)^(1/2)-1/6)/(-2), ((2737/36)^(1/2)+1/6)/2}

r in { ((2737/36)^(1/2)-1/6)/(-2), ((2737/36)^(1/2)+1/6)/2 }

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