1/6d+(2/3)=(1/4(d-2))

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Solution for 1/6d+(2/3)=(1/4(d-2)) equation: 



1/6d+(2/3)=(1/4(d-2))

We move all terms to the left:

1/6d+(2/3)-((1/4(d-2)))=0



Domain of the equation: 6d!=0

d!=0/6

d!=0

d∈R





Domain of the equation: 4(d-2)))!=0

d∈R



We add all the numbers together, and all the variables

1/6d-((1/4(d-2)))+(+2/3)=0

We get rid of parentheses

1/6d-((1/4(d-2)))+2/3=0

We calculate fractions


(12dd/(72d^2d+(-((1*6d*3)/(72d^2d+192d^2/(72d^2d=0

We can not solve this equation

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