1/6d+1/4d=-4

Solution for 1/6d+1/4d=-4 equation:

1/6d+1/4d=-4

We move all terms to the left:

1/6d+1/4d-(-4)=0


Domain of the equation: 6d!=0

d!=0/6

d!=0

d∈R



Domain of the equation: 4d!=0

d!=0/4

d!=0

d∈R


We add all the numbers together, and all the variables

1/6d+1/4d+4=0

We calculate fractions


4d/24d^2+6d/24d^2+4=0

We multiply all the terms by the denominator


4d+6d+4*24d^2=0

We add all the numbers together, and all the variables

10d+4*24d^2=0

Wy multiply elements

96d^2+10d=0

a = 96; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·96·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*96}=\frac{-20}{192}
=-5/48
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*96}=\frac{0}{192}
=0
$