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1/6k+1/8k=1
We move all terms to the left:
1/6k+1/8k-(1)=0
Domain of the equation: 6k!=0
k!=0/6
k!=0
k∈R
Domain of the equation: 8k!=0We calculate fractions
k!=0/8
k!=0
k∈R
8k/48k^2+6k/48k^2-1=0
We multiply all the terms by the denominator
8k+6k-1*48k^2=0
We add all the numbers together, and all the variables
14k-1*48k^2=0
Wy multiply elements
-48k^2+14k=0
a = -48; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-48)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-48}=\frac{-28}{-96} =7/24 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-48}=\frac{0}{-96} =0 $
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