1/6k2=1/3k2-1/k

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Solution for 1/6k2=1/3k2-1/k equation:


D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

(1/6)*k^2 = (1/3)*k^2-(1/k) // - (1/3)*k^2-(1/k)

(1/6)*k^2-((1/3)*k^2)+1/k = 0

(1/6)*k^2+(-1/3)*k^2+1/k = 0

k^-1-1/6*k^2 = 0

k^-1*(1-1/6*k^3) = 0

-1/6*k^3 = -1 // : -1/6

k^3 = 6

k^3 = 6 // ^ 1/3

k = 6^(1/3)

1/k = 0

1*k^-1 = 0 // : 1

k^-1 = 0

k naleu017Cy do O

k = 6^(1/3)

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