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1/6x+2/3x+4=x+2
We move all terms to the left:
1/6x+2/3x+4-(x+2)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
1/6x+2/3x-x-2+4=0
We calculate fractions
-x+3x/18x^2+12x/18x^2-2+4=0
We add all the numbers together, and all the variables
-1x+3x/18x^2+12x/18x^2+2=0
We multiply all the terms by the denominator
-1x*18x^2+3x+12x+2*18x^2=0
We add all the numbers together, and all the variables
15x-1x*18x^2+2*18x^2=0
Wy multiply elements
-18x^3+36x^2+15x=0
We do not support expression: x^3
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