1/6x+2/3x=650

Solution for 1/6x+2/3x=650 equation:

1/6x+2/3x=650

We move all terms to the left:

1/6x+2/3x-(650)=0


Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We calculate fractions


3x/18x^2+12x/18x^2-650=0

We multiply all the terms by the denominator


3x+12x-650*18x^2=0

We add all the numbers together, and all the variables

15x-650*18x^2=0

Wy multiply elements

-11700x^2+15x=0

a = -11700; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-11700)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-11700}=\frac{-30}{-23400}
=1/780
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-11700}=\frac{0}{-23400}
=0
$