1/6x+2=1/2x-2

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Solution for 1/6x+2=1/2x-2 equation:



1/6x+2=1/2x-2
We move all terms to the left:
1/6x+2-(1/2x-2)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 2x-2)!=0
x∈R
We get rid of parentheses
1/6x-1/2x+2+2=0
We calculate fractions
2x/12x^2+(-6x)/12x^2+2+2=0
We add all the numbers together, and all the variables
2x/12x^2+(-6x)/12x^2+4=0
We multiply all the terms by the denominator
2x+(-6x)+4*12x^2=0
Wy multiply elements
48x^2+2x+(-6x)=0
We get rid of parentheses
48x^2+2x-6x=0
We add all the numbers together, and all the variables
48x^2-4x=0
a = 48; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·48·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*48}=\frac{0}{96} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*48}=\frac{8}{96} =1/12 $

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