If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/6x+3=x/2
We move all terms to the left:
1/6x+3-(x/2)=0
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
1/6x-(+x/2)+3=0
We get rid of parentheses
1/6x-x/2+3=0
We calculate fractions
There is no solution for this equation
| -17x-11=-133 | | 2x/5+3=7/2 | | 8*x-9=19 | | 1/6x+2=(x-3)/2 | | x5=7x-168 | | -29x^2+(2x^2-11)^2+23=0 | | -29x^2+(2x^2-11)^2=-23 | | (2x^2-11)^2-6=29(x^2-1) | | x×5=(x-24)×7 | | 1/6x+6=(x-3)/2 | | -(x-4)+2(4x-3)=5 | | -3-4x=10 | | 7(x3)=49 | | 2(x-3)-4x=2 | | 2(x-3)-4x=2 | | 5x+11=17−9x | | (8x+3)-(10x+6)=9 | | 7(4w+1)÷5=0 | | -5(2t+3)=-45 | | -7x-23=9x+121 | | 29(x+1)=x | | 29x+6=-2+31x | | 5x-7=-8+3x | | 9(x-11)=x | | 104x+4=100 | | 25x^2+(-40x^2-24x+25x+15)^2+30x-(-9)=0 | | |2x-5|=|3x+10| | | -9x+27=3x-33 | | 25x^2+(-40x^2-24x+25x+15)^2+30x=-9 | | 5x-12=-6x+21 | | 9+25x^2+30x+(5-8x)(5x+3)^2=0 | | 8x=3(x+20 |