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1/6x+3x=76
We move all terms to the left:
1/6x+3x-(76)=0
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
3x+1/6x-76=0
We multiply all the terms by the denominator
3x*6x-76*6x+1=0
Wy multiply elements
18x^2-456x+1=0
a = 18; b = -456; c = +1;
Δ = b2-4ac
Δ = -4562-4·18·1
Δ = 207864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{207864}=\sqrt{36*5774}=\sqrt{36}*\sqrt{5774}=6\sqrt{5774}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-456)-6\sqrt{5774}}{2*18}=\frac{456-6\sqrt{5774}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-456)+6\sqrt{5774}}{2*18}=\frac{456+6\sqrt{5774}}{36} $
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