1/6x+42+2/5x-8/3x-10

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Solution for 1/6x+42+2/5x-8/3x-10 equation: 


x in (-oo:+oo)

(1/6)*x+(2/5)*x-((8/3)*x)-10+42 = 0

(1/6)*x+(2/5)*x+(-8/3)*x-10+42 = 0

32-21/10*x = 0 // - 32

-21/10*x = -32 // : -21/10

x = -32/(-21/10)

x = 320/21

x = 320/21

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