1/6x+42+2/5x-8/3x-19

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Solution for 1/6x+42+2/5x-8/3x-19 equation: 


x in (-oo:+oo)

(1/6)*x+(2/5)*x-((8/3)*x)-19+42 = 0

(1/6)*x+(2/5)*x+(-8/3)*x-19+42 = 0

23-21/10*x = 0 // - 23

-21/10*x = -23 // : -21/10

x = -23/(-21/10)

x = 230/21

x = 230/21

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