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1/6x+4x=4
We move all terms to the left:
1/6x+4x-(4)=0
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
4x+1/6x-4=0
We multiply all the terms by the denominator
4x*6x-4*6x+1=0
Wy multiply elements
24x^2-24x+1=0
a = 24; b = -24; c = +1;
Δ = b2-4ac
Δ = -242-4·24·1
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{30}}{2*24}=\frac{24-4\sqrt{30}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{30}}{2*24}=\frac{24+4\sqrt{30}}{48} $
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