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1/6x+54-19=x
We move all terms to the left:
1/6x+54-19-(x)=0
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
-1x+1/6x+35=0
We multiply all the terms by the denominator
-1x*6x+35*6x+1=0
Wy multiply elements
-6x^2+210x+1=0
a = -6; b = 210; c = +1;
Δ = b2-4ac
Δ = 2102-4·(-6)·1
Δ = 44124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{44124}=\sqrt{4*11031}=\sqrt{4}*\sqrt{11031}=2\sqrt{11031}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(210)-2\sqrt{11031}}{2*-6}=\frac{-210-2\sqrt{11031}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(210)+2\sqrt{11031}}{2*-6}=\frac{-210+2\sqrt{11031}}{-12} $
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