1/6x+7=1/4x+3

Solution for 1/6x+7=1/4x+3 equation:

1/6x+7=1/4x+3

We move all terms to the left:

1/6x+7-(1/4x+3)=0


Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R



Domain of the equation: 4x+3)!=0

x∈R


We get rid of parentheses

1/6x-1/4x-3+7=0

We calculate fractions


4x/24x^2+(-6x)/24x^2-3+7=0

We add all the numbers together, and all the variables

4x/24x^2+(-6x)/24x^2+4=0

We multiply all the terms by the denominator


4x+(-6x)+4*24x^2=0

Wy multiply elements

96x^2+4x+(-6x)=0

We get rid of parentheses

96x^2+4x-6x=0

We add all the numbers together, and all the variables

96x^2-2x=0

a = 96; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·96·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*96}=\frac{0}{192}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*96}=\frac{4}{192}
=1/48
$