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1/6x+9=1/8(x+5)
We move all terms to the left:
1/6x+9-(1/8(x+5))=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 8(x+5))!=0We calculate fractions
x∈R
(8xx/(48x^2x+(-(1*6x)/(48x^2x+9=0
We can not solve this equation
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