1/6x+x=28

Solution for 1/6x+x=28 equation:

1/6x+x=28

We move all terms to the left:

1/6x+x-(28)=0


Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R


We add all the numbers together, and all the variables

x+1/6x-28=0

We multiply all the terms by the denominator


x*6x-28*6x+1=0

Wy multiply elements

6x^2-168x+1=0

a = 6; b = -168; c = +1;
Δ = b2-4ac
Δ = -1682-4·6·1
Δ = 28200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28200}=\sqrt{100*282}=\sqrt{100}*\sqrt{282}=10\sqrt{282}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-168)-10\sqrt{282}}{2*6}=\frac{168-10\sqrt{282}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-168)+10\sqrt{282}}{2*6}=\frac{168+10\sqrt{282}}{12}
$