1/6x-11=2/3x+4

Solution for 1/6x-11=2/3x+4 equation:

1/6x-11=2/3x+4

We move all terms to the left:

1/6x-11-(2/3x+4)=0


Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R



Domain of the equation: 3x+4)!=0

x∈R


We get rid of parentheses

1/6x-2/3x-4-11=0

We calculate fractions


3x/18x^2+(-12x)/18x^2-4-11=0

We add all the numbers together, and all the variables

3x/18x^2+(-12x)/18x^2-15=0

We multiply all the terms by the denominator


3x+(-12x)-15*18x^2=0

Wy multiply elements

-270x^2+3x+(-12x)=0

We get rid of parentheses

-270x^2+3x-12x=0

We add all the numbers together, and all the variables

-270x^2-9x=0

a = -270; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·(-270)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*-270}=\frac{0}{-540}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*-270}=\frac{18}{-540}
=-1/30
$