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1/6x=2x-5
We move all terms to the left:
1/6x-(2x-5)=0
Domain of the equation: 6x!=0We get rid of parentheses
x!=0/6
x!=0
x∈R
1/6x-2x+5=0
We multiply all the terms by the denominator
-2x*6x+5*6x+1=0
Wy multiply elements
-12x^2+30x+1=0
a = -12; b = 30; c = +1;
Δ = b2-4ac
Δ = 302-4·(-12)·1
Δ = 948
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{948}=\sqrt{4*237}=\sqrt{4}*\sqrt{237}=2\sqrt{237}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{237}}{2*-12}=\frac{-30-2\sqrt{237}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{237}}{2*-12}=\frac{-30+2\sqrt{237}}{-24} $
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