1/6y+25=y

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Solution for 1/6y+25=y equation:



1/6y+25=y
We move all terms to the left:
1/6y+25-(y)=0
Domain of the equation: 6y!=0
y!=0/6
y!=0
y∈R
We add all the numbers together, and all the variables
-1y+1/6y+25=0
We multiply all the terms by the denominator
-1y*6y+25*6y+1=0
Wy multiply elements
-6y^2+150y+1=0
a = -6; b = 150; c = +1;
Δ = b2-4ac
Δ = 1502-4·(-6)·1
Δ = 22524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{22524}=\sqrt{4*5631}=\sqrt{4}*\sqrt{5631}=2\sqrt{5631}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-2\sqrt{5631}}{2*-6}=\frac{-150-2\sqrt{5631}}{-12} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+2\sqrt{5631}}{2*-6}=\frac{-150+2\sqrt{5631}}{-12} $

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