1/6y+3/4y=12

Solution for 1/6y+3/4y=12 equation:

1/6y+3/4y=12

We move all terms to the left:

1/6y+3/4y-(12)=0


Domain of the equation: 6y!=0

y!=0/6

y!=0

y∈R



Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R


We calculate fractions


4y/24y^2+18y/24y^2-12=0

We multiply all the terms by the denominator


4y+18y-12*24y^2=0

We add all the numbers together, and all the variables

22y-12*24y^2=0

Wy multiply elements

-288y^2+22y=0

a = -288; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·(-288)·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*-288}=\frac{-44}{-576}
=11/144
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*-288}=\frac{0}{-576}
=0
$