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1/6y=-1/3(y+1)
We move all terms to the left:
1/6y-(-1/3(y+1))=0
Domain of the equation: 6y!=0
y!=0/6
y!=0
y∈R
Domain of the equation: 3(y+1))!=0We calculate fractions
y∈R
(3yy/(18y^2y+(-(-1*6y)/(18y^2y=0
We can not solve this equation
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