1/6z+12=24

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Solution for 1/6z+12=24 equation: 



1/6z+12=24

We move all terms to the left:

1/6z+12-(24)=0



Domain of the equation: 6z!=0

z!=0/6

z!=0

z∈R



We add all the numbers together, and all the variables

1/6z-12=0

We multiply all the terms by the denominator


-12*6z+1=0

Wy multiply elements

-72z+1=0

We move all terms containing z to the left, all other terms to the right

-72z=-1

z=-1/-72

z=1/72

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