1/7(10x+28)=5

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Solution for 1/7(10x+28)=5 equation: 



1/7(10x+28)=5

We move all terms to the left:

1/7(10x+28)-(5)=0



Domain of the equation: 7(10x+28)!=0

x∈R



We multiply all the terms by the denominator


-5*7(10x+28)+1=0

Wy multiply elements

-35x(1+1=0

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