1/7(14r+28)-3r=6

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Solution for 1/7(14r+28)-3r=6 equation: 



1/7(14r+28)-3r=6

We move all terms to the left:

1/7(14r+28)-3r-(6)=0



Domain of the equation: 7(14r+28)!=0

r∈R



We add all the numbers together, and all the variables

-3r+1/7(14r+28)-6=0

We multiply all the terms by the denominator


-3r*7(14r+28)-6*7(14r+28)+1=0

Wy multiply elements

-21r^2(1-42r(1+1=0

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