1/7(21a-7b)-1/3(12b-6a)

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Solution for 1/7(21a-7b)-1/3(12b-6a) equation: 


x in (-oo:+oo)

(1/7)*(21*a-(7*b))-((1/3)*(12*b-(6*a))) = 0

(1/7)*(21*a-7*b)+(-1/3)*(12*b-6*a) = 0

1/7*(21*a-7*b)-1/3*(12*b-6*a) = 0

1/7*(21*a-7*b)-1/3*(12*b-6*a) = 0

5*a-5*b = 0

5*a-5*b = 0

x belongs to the empty set

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