1/7(2x-5)=2/7x+1

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Solution for 1/7(2x-5)=2/7x+1 equation: 


x in (-oo:+oo)

(1/7)*(2*x-5) = (2/7)*x+1 // - (2/7)*x+1

(1/7)*(2*x-5)-((2/7)*x)-1 = 0

(1/7)*(2*x-5)+(-2/7)*x-1 = 0

1/7*(2*x-5)+(-2*x)/7-1 = 0

(1/7*7*(2*x-5))/7+(-2*x)/7+(-1*7)/7 = 0

1/7*7*(2*x-5)-2*x-1*7 = 0

-7-5 = 0

-12 = 0

-12/7 = 0

-12/7 = 0 // * 7

-12 = 0

x belongs to the empty set

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