1/7(3(x-1)+19)=x

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Solution for 1/7(3(x-1)+19)=x equation: 



1/7(3(x-1)+19)=x

We move all terms to the left:

1/7(3(x-1)+19)-(x)=0



Domain of the equation: 7(3(x-1)+19)!=0

x∈R



We add all the numbers together, and all the variables

-1x+1/7(3(x-1)+19)=0

We multiply all the terms by the denominator


-1x*7(3(x-1)+19)+1=0

Wy multiply elements

-7x^2(3+1=0

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