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1/7(3t-4)=1/14(t+4)
We move all terms to the left:
1/7(3t-4)-(1/14(t+4))=0
Domain of the equation: 7(3t-4)!=0
t∈R
Domain of the equation: 14(t+4))!=0We calculate fractions
t∈R
(14tt/(7(3t-4)*14(t+4)))+(-7t3/(7(3t-4)*14(t+4)))=0
We calculate terms in parentheses: +(14tt/(7(3t-4)*14(t+4))), so:
14tt/(7(3t-4)*14(t+4))
We multiply all the terms by the denominator
14tt
Back to the equation:
+(14tt)
We calculate terms in parentheses: +(-7t3/(7(3t-4)*14(t+4))), so:
-7t3/(7(3t-4)*14(t+4))
We multiply all the terms by the denominator
-7t3
We add all the numbers together, and all the variables
-7t^3
We do not support etpression: t^3
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