1/7(3t-4)=1/14(t+4)

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Solution for 1/7(3t-4)=1/14(t+4) equation: 



1/7(3t-4)=1/14(t+4)

We move all terms to the left:

1/7(3t-4)-(1/14(t+4))=0



Domain of the equation: 7(3t-4)!=0

t∈R





Domain of the equation: 14(t+4))!=0

t∈R



We calculate fractions


(14tt/(7(3t-4)*14(t+4)))+(-7t3/(7(3t-4)*14(t+4)))=0



We calculate terms in parentheses: +(14tt/(7(3t-4)*14(t+4))), so:

14tt/(7(3t-4)*14(t+4))

We multiply all the terms by the denominator


14tt

Back to the equation:

+(14tt)





We calculate terms in parentheses: +(-7t3/(7(3t-4)*14(t+4))), so:

-7t3/(7(3t-4)*14(t+4))

We multiply all the terms by the denominator


-7t3

We add all the numbers together, and all the variables

-7t^3

We do not support etpression: t^3

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