1/7(3x+12)-1/2(x+4)=2

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Solution for 1/7(3x+12)-1/2(x+4)=2 equation: 


x in (-oo:+oo)

(1/7)*(3*x+12)-((1/2)*(x+4)) = 2 // - 2

(1/7)*(3*x+12)-((1/2)*(x+4))-2 = 0

(1/7)*(3*x+12)+(-1/2)*(x+4)-2 = 0

1/7*(3*x+12)-1/2*(x+4)-2 = 0

1/7*(3*x+12)-1/2*(x+4)-2 = 0

-1/14*x-2-2/7 = 0

-1/14*x-16/7 = 0

-1/14*x-16/7 = 0

-1/14*x-16/7 = 0 // + 16/7

-1/14*x = 16/7 // : -1/14

x = 16/7/(-1/14)

x = -32

x = -32

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