1/7(3x+12)-1/5(x+4)=2

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Solution for 1/7(3x+12)-1/5(x+4)=2 equation: 


x in (-oo:+oo)

(1/7)*(3*x+12)-((1/5)*(x+4)) = 2 // - 2

(1/7)*(3*x+12)-((1/5)*(x+4))-2 = 0

(1/7)*(3*x+12)+(-1/5)*(x+4)-2 = 0

1/7*(3*x+12)-1/5*(x+4)-2 = 0

1/7*(3*x+12)-1/5*(x+4)-2 = 0

8/35*x-2+32/35 = 0

8/35*x-38/35 = 0

8/35*x-38/35 = 0

8/35*x-38/35 = 0 // + 38/35

8/35*x = 38/35 // : 8/35

x = 38/35/8/35

x = 19/4

x = 19/4

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