1/7(3x+2)-1/3(x+8)=6

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Solution for 1/7(3x+2)-1/3(x+8)=6 equation: 


x in (-oo:+oo)

(1/7)*(3*x+2)-((1/3)*(x+8)) = 6 // - 6

(1/7)*(3*x+2)-((1/3)*(x+8))-6 = 0

(1/7)*(3*x+2)+(-1/3)*(x+8)-6 = 0

1/7*(3*x+2)-1/3*(x+8)-6 = 0

1/7*(3*x+2)-1/3*(x+8)-6 = 0

2/21*x-6-50/21 = 0

2/21*x-176/21 = 0

2/21*x-176/21 = 0

2/21*x-176/21 = 0 // + 176/21

2/21*x = 176/21 // : 2/21

x = 176/21/2/21

x = 88

x = 88

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