1/7(3x+2)-1/5(x+4)=2

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Solution for 1/7(3x+2)-1/5(x+4)=2 equation:


1/7(3x+2)-1/5(x+4)=2

We simplify the equation to the form, which is simple to understand
1/7(3x+2)-1/5(x+4)=2

Simplifying:
+ 0.142857142857*(3x+2)-1/5*(x+4)=2

Simplifying:
+ 0.142857142857*(3x+2)-0.2*(x+4)=2

Reorder the terms in parentheses
+( + 0.428571428571x + 0.285714285714)-0.2*(x+4)=2

Remove unnecessary parentheses
+ 0.428571428571x + 0.285714285714-0.2+*(+x+4+)=+2

Reorder the terms in parentheses
+ 0.428571428571x + 0.285714285714+(-0.2x-0.8)=2

Remove unnecessary parentheses
+ 0.428571428571x + 0.285714285714-0.2x-0.8=+2

We move all terms containing x to the left and all other terms to the right.
+ 0.428571428571x-0.2x=+2-0.285714285714 + 0.8

We simplify left and right side of the equation.
+ 0.228571428571x=+2.51428571429

We divide both sides of the equation by 0.228571428571 to get x.
x=11

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