1/7(3x-2)=X/5+10/5

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Solution for 1/7(3x-2)=X/5+10/5 equation: 


x in (-oo:+oo)

(1/7)*(3*x-2) = X/5+10/5 // - X/5+10/5

(1/7)*(3*x-2)-(X/5)-(10/5) = 0

(1/7)*(3*x-2)-(X/5)-2 = 0

1/7*(3*x-2)-X/5-2 = 0

(1/7*5*(3*x-2))/5-X/5+(-2*5)/5 = 0

1/7*5*(3*x-2)-X-2*5 = 0

15/7*x-X-10-10/7 = 0

15/7*x-X-80/7 = 0

(15/7*x-X-80/7)/5 = 0

(15/7*x-X-80/7)/5 = 0 // * 5

15/7*x-X-80/7 = 0

15/7*x-X-80/7 = 0 // + -X-80/7

15/7*x = -(-X-80/7) // : 15/7

x = (-(-X-80/7))/15/7

x = 7/15*(X+80/7)

x = 7/15*(X+80/7)

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