1/7(3x-2)=x+10/5

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Solution for 1/7(3x-2)=x+10/5 equation: 



1/7(3x-2)=x+10/5

We move all terms to the left:

1/7(3x-2)-(x+10/5)=0



Domain of the equation: 7(3x-2)!=0

x∈R



We add all the numbers together, and all the variables

1/7(3x-2)-(x+2)=0

We get rid of parentheses

1/7(3x-2)-x-2=0

We multiply all the terms by the denominator


-x*7(3x-2)-2*7(3x-2)+1=0

Wy multiply elements

-7x^2(3-14x(3+1=0

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