1/7(3y+2)=2+1/3(y+2)

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Solution for 1/7(3y+2)=2+1/3(y+2) equation:


1/7(3y+2)=2+1/3(y+2)

We simplify the equation to the form, which is simple to understand
1/7(3y+2)=2+1/3(y+2)

Simplifying:
+ 0.142857142857*(3y+2)=2+1/3*(y+2)

Simplifying:
+ 0.142857142857*(3y+2)=2 + 0.333333333333*(y+2)

Reorder the terms in parentheses
+( + 0.428571428571y + 0.285714285714)=2 + 0.333333333333*(y+2)

Remove unnecessary parentheses
+ 0.428571428571y + 0.285714285714=+2 + 0.333333333333+*(+y+2+)

Reorder the terms in parentheses
+ 0.428571428571y + 0.285714285714=2+( + 0.333333333333y + 0.666666666667)

Remove unnecessary parentheses
+ 0.428571428571y + 0.285714285714=+2 + 0.333333333333y + 0.666666666667

We move all terms containing y to the left and all other terms to the right.
+ 0.428571428571y-0.333333333333y=+2 + 0.666666666667-0.285714285714

We simplify left and right side of the equation.
+ 0.0952380952384y=+2.38095238095

We divide both sides of the equation by 0.0952380952384 to get y.
y=24.9999999999

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