1/7(3y+4)=5+1/5(y+3)

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Solution for 1/7(3y+4)=5+1/5(y+3) equation: 


y in (-oo:+oo)

(1/7)*(3*y+4) = (1/5)*(y+3)+5 // - (1/5)*(y+3)+5

(1/7)*(3*y+4)-((1/5)*(y+3))-5 = 0

(1/7)*(3*y+4)+(-1/5)*(y+3)-5 = 0

1/7*(3*y+4)-1/5*(y+3)-5 = 0

1/7*(3*y+4)-1/5*(y+3)-5 = 0

8/35*y-5-1/35 = 0

8/35*y-176/35 = 0

8/35*y-176/35 = 0

8/35*y-176/35 = 0 // + 176/35

8/35*y = 176/35 // : 8/35

y = 176/35/8/35

y = 22

y = 22

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