1/7(42x-63)+x=7(x-1)-2

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Solution for 1/7(42x-63)+x=7(x-1)-2 equation: 



1/7(42x-63)+x=7(x-1)-2

We move all terms to the left:

1/7(42x-63)+x-(7(x-1)-2)=0



Domain of the equation: 7(42x-63)!=0

x∈R



We add all the numbers together, and all the variables

x+1/7(42x-63)-(7(x-1)-2)=0

We multiply all the terms by the denominator


x*7(42x-63)-((7(x-1)-2))*7(42x-63)+1=0



We calculate terms in parentheses: -((7(x-1)-2))*7(42x-63), so:

(7(x-1)-2))*7(42x-63



Wy multiply elements

7x^2(4-((7(x-1)-2))*7(42x-63)+1=0

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