1/7(49-14)=-1/6(36x-42)

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Solution for 1/7(49-14)=-1/6(36x-42) equation: 



1/7(49-14)=-1/6(36x-42)

We move all terms to the left:

1/7(49-14)-(-1/6(36x-42))=0



Domain of the equation: 6(36x-42))!=0

x∈R



We add all the numbers together, and all the variables

-(-1/6(36x-42))+1/735=0

We calculate fractions


()/158760x+(6x3/158760x=0

We multiply all the terms by the denominator


(6x3+()=0



We calculate terms in parentheses: +(6x3+(), so:

6x3+(

We add all the numbers together, and all the variables

6x^3

We do not support expression: x^3

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