1/7(5-9x)=1/3(9+3x)

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Solution for 1/7(5-9x)=1/3(9+3x) equation: 



1/7(5-9x)=1/3(9+3x)

We move all terms to the left:

1/7(5-9x)-(1/3(9+3x))=0



Domain of the equation: 7(5-9x)!=0

x∈R





Domain of the equation: 3(9+3x))!=0

x∈R



We add all the numbers together, and all the variables

1/7(-9x+5)-(1/3(3x+9))=0

We calculate fractions


(3x3/(7(-9x+5)*3(3x+9)))+(-7x0/(7(-9x+5)*3(3x+9)))=0



We calculate terms in parentheses: +(3x3/(7(-9x+5)*3(3x+9))), so:

3x3/(7(-9x+5)*3(3x+9))

We multiply all the terms by the denominator


3x3

We add all the numbers together, and all the variables

3x^3

We do not support expression: x^3

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