1/7(6u+7)-u=4/3(2u-8)+3/7

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Solution for 1/7(6u+7)-u=4/3(2u-8)+3/7 equation: 


u in (-oo:+oo)

(1/7)*(6*u+7)-u = (4/3)*(2*u-8)+3/7 // - (4/3)*(2*u-8)+3/7

(1/7)*(6*u+7)-((4/3)*(2*u-8))-u-(3/7) = 0

(1/7)*(6*u+7)+(-4/3)*(2*u-8)-u-3/7 = 0

1/7*(6*u+7)-4/3*(2*u-8)-u-3/7 = 0

(1/7*7*(6*u+7))/7+(-4/3*7*(2*u-8))/7+(7*(-u))/7-3/7 = 0

1/7*7*(6*u+7)-4/3*7*(2*u-8)+7*(-u)-3 = 0

245/3-38/3*u-7*u-3 = 0

245/3-59/3*u-3 = 0

236/3-59/3*u = 0

(236/3-59/3*u)/7 = 0

(236/3-59/3*u)/7 = 0 // * 7

236/3-59/3*u = 0

236/3-59/3*u = 0 // - 236/3

-59/3*u = -236/3 // : -59/3

u = -236/3/(-59/3)

u = 4

u = 4

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