1/7(7y+28)-6=-1/3(6y-21)

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Solution for 1/7(7y+28)-6=-1/3(6y-21) equation: 



1/7(7y+28)-6=-1/3(6y-21)

We move all terms to the left:

1/7(7y+28)-6-(-1/3(6y-21))=0



Domain of the equation: 7(7y+28)!=0

y∈R





Domain of the equation: 3(6y-21))!=0

y∈R



We calculate fractions


(3y6/(7(7y+28)*3(6y-21)))+(-(-7y7)/(7(7y+28)*3(6y-21)))-6=0



We calculate terms in parentheses: +(3y6/(7(7y+28)*3(6y-21))), so:

3y6/(7(7y+28)*3(6y-21))

We multiply all the terms by the denominator


3y6

We add all the numbers together, and all the variables

3y^6

We do not support eypression: y^6

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