1/7(7y+28)-6=-1/8(16y-56)

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Solution for 1/7(7y+28)-6=-1/8(16y-56) equation: 



1/7(7y+28)-6=-1/8(16y-56)

We move all terms to the left:

1/7(7y+28)-6-(-1/8(16y-56))=0



Domain of the equation: 7(7y+28)!=0

y∈R





Domain of the equation: 8(16y-56))!=0

y∈R



We calculate fractions


(8y1/(7(7y+28)*8(16y-56)))+(-(-7y7)/(7(7y+28)*8(16y-56)))-6=0



We calculate terms in parentheses: +(8y1/(7(7y+28)*8(16y-56))), so:

8y1/(7(7y+28)*8(16y-56))

We multiply all the terms by the denominator


8y1

We add all the numbers together, and all the variables

8y

Back to the equation:

+(8y)





We calculate terms in parentheses: +(-(-7y7)/(7(7y+28)*8(16y-56))), so:

-(-7y7)/(7(7y+28)*8(16y-56))

We add all the numbers together, and all the variables

-(-7y^7)/(7(7y+28)*8(16y-56))

We multiply all the terms by the denominator


-(-7y^7)

We do not support eypression: y^7

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