1/7(a+3)=1/6(5-a)

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Solution for 1/7(a+3)=1/6(5-a) equation: 



1/7(a+3)=1/6(5-a)

We move all terms to the left:

1/7(a+3)-(1/6(5-a))=0



Domain of the equation: 7(a+3)!=0

a∈R





Domain of the equation: 6(5-a))!=0

a∈R



We add all the numbers together, and all the variables

1/7(a+3)-(1/6(-1a+5))=0

We calculate fractions


(6a(-)/(7(a+3)*6(-1a+5)))+(-7aa/(7(a+3)*6(-1a+5)))=0



We calculate terms in parentheses: +(6a(-)/(7(a+3)*6(-1a+5))), so:

6a(-)/(7(a+3)*6(-1a+5))

We add all the numbers together, and all the variables

6a0/(7(a+3)*6(-1a+5))

We multiply all the terms by the denominator


6a0

We add all the numbers together, and all the variables

6a

Back to the equation:

+(6a)





We calculate terms in parentheses: +(-7aa/(7(a+3)*6(-1a+5))), so:

-7aa/(7(a+3)*6(-1a+5))

We multiply all the terms by the denominator


-7aa

Back to the equation:

+(-7aa)



We get rid of parentheses

6a-7aa=0

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