1/7(a+6)=1/2(2-a)

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Solution for 1/7(a+6)=1/2(2-a) equation: 



1/7(a+6)=1/2(2-a)

We move all terms to the left:

1/7(a+6)-(1/2(2-a))=0



Domain of the equation: 7(a+6)!=0

a∈R





Domain of the equation: 2(2-a))!=0

a∈R



We add all the numbers together, and all the variables

1/7(a+6)-(1/2(-1a+2))=0

We calculate fractions


(2a(-)/(7(a+6)*2(-1a+2)))+(-7aa/(7(a+6)*2(-1a+2)))=0



We calculate terms in parentheses: +(2a(-)/(7(a+6)*2(-1a+2))), so:

2a(-)/(7(a+6)*2(-1a+2))

We add all the numbers together, and all the variables

2a0/(7(a+6)*2(-1a+2))

We multiply all the terms by the denominator


2a0

We add all the numbers together, and all the variables

2a

Back to the equation:

+(2a)





We calculate terms in parentheses: +(-7aa/(7(a+6)*2(-1a+2))), so:

-7aa/(7(a+6)*2(-1a+2))

We multiply all the terms by the denominator


-7aa

Back to the equation:

+(-7aa)



We get rid of parentheses

2a-7aa=0

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