1/7(a-3)(7a+4)=0

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Solution for 1/7(a-3)(7a+4)=0 equation:


a in (-oo:+oo)

(1/7)*(a-3)*(7*a+4) = 0

1/7*(a-3)*(7*a+4) = 0

( 7*a+4 )

7*a+4 = 0 // - 4

7*a = -4 // : 7

a = -4/7

( a-3 )

a-3 = 0 // + 3

a = 3

a in { -4/7, 3 }

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