1/7(a-4)=1/3(2a+4)

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Solution for 1/7(a-4)=1/3(2a+4) equation: 



1/7(a-4)=1/3(2a+4)

We move all terms to the left:

1/7(a-4)-(1/3(2a+4))=0



Domain of the equation: 7(a-4)!=0

a∈R





Domain of the equation: 3(2a+4))!=0

a∈R



We calculate fractions


(3a2/(7(a-4)*3(2a+4)))+(-7aa/(7(a-4)*3(2a+4)))=0



We calculate terms in parentheses: +(3a2/(7(a-4)*3(2a+4))), so:

3a2/(7(a-4)*3(2a+4))

We multiply all the terms by the denominator


3a2

We add all the numbers together, and all the variables

3a^2

Back to the equation:

+(3a^2)





We calculate terms in parentheses: +(-7aa/(7(a-4)*3(2a+4))), so:

-7aa/(7(a-4)*3(2a+4))

We multiply all the terms by the denominator


-7aa

Back to the equation:

+(-7aa)



We get rid of parentheses

3a^2-7aa=0

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