1/7(b+2)=2+b

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Solution for 1/7(b+2)=2+b equation: 



1/7(b+2)=2+b

We move all terms to the left:

1/7(b+2)-(2+b)=0



Domain of the equation: 7(b+2)!=0

b∈R



We add all the numbers together, and all the variables

1/7(b+2)-(b+2)=0

We get rid of parentheses

1/7(b+2)-b-2=0

We multiply all the terms by the denominator


-b*7(b+2)-2*7(b+2)+1=0

Wy multiply elements

-7b^2(b-14b(b+1=0

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