1/7(b+35)=3

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Solution for 1/7(b+35)=3 equation: 


b in (-oo:+oo)

(1/7)*(b+35) = 3 // - 3

(1/7)*(b+35)-3 = 0

1/7*(b+35)-3 = 0

1/7*(b+35)-3 = 0

1/7*b+2 = 0

1/7*b+2 = 0

1/7*b+2 = 0 // - 2

1/7*b = -2 // : 1/7

b = -2/1/7

b = -14

b = -14

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